A cat rides a bicycle down a hill. At the top of the hill, the cat is traveling with an initial speed of 3.1 meters per second. 6 seconds later, the speed increases to 7.5 meters per second. What is the acceleration of the bicycle-riding cat?
The secret to solving word problems is to G.U.E.S.S.!
Before we continue, take a look and notice that you have translated to word problem to a regular problem. Yay!
Once you are done GUESSing, you will have the answer to your word problem. Now let's see how it works!
Reading the probelem gives us this information:
The question at the end of the problem usually tells us what the unknown is.
This problem is in the topic of 1-D Motion, or Kinematic Equations. There are only 3 equations relating to this topic; one equation relates our givens and unknown.
The first equation contains the unknown. Also, all the other variables in the equation are given. (If we tried either of the other equations we would be stumped on the displacement variable $s$).
Believe it or not, at this point the problem is pretty much solved. A little bit of Algebra 1 is all that remains. There are a couple of different ways this can be done...
If you are uncomfortable manipulating an equation without all the numbers, you should probably substitute first. Rewrite the equation and "plug in" the values that were given. Then solve, probably using a calculator quite a bit. (Note that the units are all SI units, so they should work out.)
$$v_f = v_i + a t$$
$$7.5 = 3.1 + a \times 6$$
$$7.5 - 3.1 = a \times 6$$
$$4.4 = a \times 6$$
$$a = 4.4 \div 6$$
If you can handle it, consider solving the symbolic equation before plugging in the numbers or grabbing a calculator. Since there are only a few equations and a few variables, there can only be a relatively small number of unique problems. Solving symbolically and then plugging in the givens is a good way to start noticing that, and also reduces your calculator usage.
$$v_f = v_i + a t$$
$$v_f - v_i = a t$$
$$a = \frac {v_f - v_i}{t}$$
$$a = \frac {7.5 - 3.1}{6} = 0.73 \frac m {s^2}$$